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5x^2-2x+16=4x^2=6x
We move all terms to the left:
5x^2-2x+16-(4x^2)=0
determiningTheFunctionDomain 5x^2-4x^2-2x+16=0
We add all the numbers together, and all the variables
x^2-2x+16=0
a = 1; b = -2; c = +16;
Δ = b2-4ac
Δ = -22-4·1·16
Δ = -60
Delta is less than zero, so there is no solution for the equation
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